Sentence


Parse

Danke
N/PP
 
fürs
PP/NP
 
da
N
 
NP
*
PP
> 0
N
> 0
NP
*
NP/(NP\NP)
T >
sein
(S[b]\NP)\NP
 
(S[b]\NP)/(NP\NP)
< 1×
.
NP\NP
 
S[b]\NP
> 0

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