Sentence


Parse

Mach
N
 
's
N\N
 
,
(N\N)\(N\N)
 
N\N
< 0
N
< 0
NP
*
wie
((S[dcl]\NP)/(S[b]\NP))/NP
 
du
NP
 
(S[dcl]\NP)/(S[b]\NP)
> 0
es
NP
 
für
PP/NP
 
richtig
N
 
NP
*
PP
> 0
(S[b]\NP)/((S[b]\NP)\PP)
T >
hältst
((S[b]\NP)\PP)\NP
 
(S[b]\NP)\NP
> 1×
S[b]\NP
< 0
S[dcl]\NP
> 0
S[dcl]
< 0
.
S[dcl]\S[dcl]
 
S[dcl]
< 0

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