Sentence


Parse

Do
(S[b]\NP)/(S[b]\NP)
 
n't
(S\NP)\(S\NP)
 
(S[b]\NP)/(S[b]\NP)
< 1×
care
(S[b]\NP)/NP
 
a
NP/N
 
hang
N/PP
 
about
PP/NP
 
it
NP
 
PP
> 0
.
.
 
PP
.
N
> 0
NP
> 0
S[b]\NP
> 0
S[b]\NP
> 0

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