Sentence


Parse

Get
((S[b]\NP)/(S[adj]\NP))/NP
 
that
NP
 
(S[b]\NP)/(S[adj]\NP)
> 0
away
(S[adj]\NP)/PP
 
from
PP/NP
 
me
NP
 
PP
> 0
.
.
 
PP
.
S[adj]\NP
> 0
S[b]\NP
> 0

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