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Parse

I
NP
 
'm
(S[dcl]\NP)/(S[ng]\NP)
 
finding
(S[ng]\NP)/NP
 
that
N/(S[adj]\NP)
 
very
(S[adj]\NP)/(S[adj]\NP)
 
difficult
(S[adj]\NP)/((S[to]\NP)/NP)
 
to
(S[to]\NP)/(S[b]\NP)
 
believe
(S[b]\NP)/NP
 
.
.
 
(S[b]\NP)/NP
.
(S[to]\NP)/NP
> 1
S[adj]\NP
> 0
S[adj]\NP
> 0
N
> 0
NP
*
S[ng]\NP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0

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