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S[b]\NP

here

(S\NP)\(S\NP)

S[b]\NP

< ⁰

 <div class="der">
<table class="constituent binaryrule" data-cat="S[b]\NP">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="Stay" data-from="0" data-to="4" data-cat="S[b]\NP">
<tr><td class="token">Stay</td></tr>
<tr><td class="cat" tabindex="0">S[b]\NP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="(S\NP)\(S\NP)">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="here" data-from="5" data-to="9" data-cat="(S\NP)\(S\NP)">
<tr><td class="token">here</td></tr>
<tr><td class="cat" tabindex="0">(S\NP)\(S\NP)</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent lex" data-token="!" data-from="9" data-to="10" data-cat=".">
<tr><td class="token">!</td></tr>
<tr><td class="cat" tabindex="0">.</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">(S\NP)\(S\NP)</div>
<div class="rule" title="Remove Punctuation">.</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[b]\NP</div>
<div class="rule" title="Backward Application">&lt; <sup>0</sup>
</div>
</div></td></tr>
</table> </div>

Use with der.css.

\begin{tikzpicture}[ampersand replacement=\&]
	\matrix [column sep=9pt] at (0, 0) {
		\lexnode*{idm10}{Stay}{\catS[b]\?\catNP}{} \&
		\lexnode*{idm31}{here}{(\catS\?\catNP)\?(\catS\?\catNP)}{} \&
		\lexnode*{idm45}{!}{\cat.}{} \\
	};
	\binnode*{idm20}{idm31-cat}{idm45-cat}{.}{(\catS\?\catNP)\?(\catS\?\catNP)}{}
	\binnode*{idm3}{idm10-cat}{idm20}{\BC{0}}{\catS[b]\?\catNP}{}
\end{tikzpicture}

Use with ccgsym.sty and tikzlibraryccgder.code.tex.

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