Sentence


Parse

Thank
((S[b]\NP)/PP)/NP
 
you
NP
 
(S[b]\NP)/PP
> 0
for
PP/(S[ng]\NP)
 
being
(S[ng]\NP)/(S[adj]\NP)
 
here
S[adj]\NP
 
.
.
 
S[adj]\NP
.
S[ng]\NP
> 0
PP
> 0
S[b]\NP
> 0

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