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Thank
((S[b]\NP)/PP)/NP
 
you
NP
 
(S[b]\NP)/PP
> 0
guys
N
 
NP
*
S[X]/(S[X]\NP)
T >
for
PP/(S[ng]\NP)
 
coming
S[ng]\NP
 
.
.
 
S[ng]\NP
.
PP
> 0
(S[X]\NP)\((S[X]\NP)/PP)
T <
S[X]\((S[X]\NP)/PP)
> 1×
S[b]
< 0

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