Sentence


Parse

That
NP
 
's
(S[dcl]\NP)/(S[adj]\NP)
 
useful
(S[adj]\NP)/(S[to]\NP)
 
to
(S[to]\NP)/(S[b]\NP)
 
know
S[b]\NP
 
S[to]\NP
> 0
.
.
 
S[to]\NP
.
S[adj]\NP
> 0
S[dcl]\NP
> 0
S[dcl]
< 0

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