CCGWeb - Mij maakt het niet uit.

Mij

maakt

(S[dcl]\NP)/(S[b]\NP)

het

(S[b]\NP)/((S[b]\NP)\NP)

T ^>

(S[dcl]\NP)/((S[b]\NP)\NP)

> ¹

niet

(S[dcl]\NP)\(S[dcl]\NP)

(S[dcl]\NP)/((S[b]\NP)\NP)

< ¹_×

uit

(S[b]\NP)\NP

S[dcl]\NP

> ⁰

S[dcl]

< ⁰

S[dcl]\S[dcl]

S[dcl]

< ⁰

 <div class="der">
<table class="constituent binaryrule" data-cat="S[dcl]">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent binaryrule" data-cat="S[dcl]">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="Mij" data-from="0" data-to="3" data-cat="NP">
<tr><td class="token">Mij</td></tr>
<tr><td class="cat" tabindex="0">NP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent binaryrule" data-cat="S[dcl]\NP">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent binaryrule" data-cat="(S[dcl]\NP)/((S[b]\NP)\NP)">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent binaryrule" data-cat="(S[dcl]\NP)/((S[b]\NP)\NP)">
<tr class="daughters">
<td class="daughter daughter-left"><table class="constituent lex" data-token="maakt" data-from="4" data-to="9" data-cat="(S[dcl]\NP)/(S[b]\NP)">
<tr><td class="token">maakt</td></tr>
<tr><td class="cat" tabindex="0">(S[dcl]\NP)/(S[b]\NP)</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent unaryrule" data-cat="(S[b]\NP)/((S[b]\NP)\NP)">
<tr class="daughters"><td class="daughter daughter-only"><table class="constituent lex" data-token="het" data-from="10" data-to="13" data-cat="NP">
<tr><td class="token">het</td></tr>
<tr><td class="cat" tabindex="0">NP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td></tr>
<tr><td class="rulecat"><div class="rulecat">
<div class="cat">(S[b]\NP)/((S[b]\NP)\NP)</div>
<div class="rule" title="Forward Type Raising">
									T <sup>&gt;</sup>
</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">(S[dcl]\NP)/((S[b]\NP)\NP)</div>
<div class="rule" title="Forward Composition">&gt; <sup>1</sup>
</div>
</div></td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent lex" data-token="niet" data-from="14" data-to="18" data-cat="(S[dcl]\NP)\(S[dcl]\NP)">
<tr><td class="token">niet</td></tr>
<tr><td class="cat" tabindex="0">(S[dcl]\NP)\(S[dcl]\NP)</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">(S[dcl]\NP)/((S[b]\NP)\NP)</div>
<div class="rule" title="Backward Crossed Composition">&lt; <sup>1</sup><sub>×</sub>
</div>
</div></td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent lex" data-token="uit" data-from="19" data-to="22" data-cat="(S[b]\NP)\NP">
<tr><td class="token">uit</td></tr>
<tr><td class="cat" tabindex="0">(S[b]\NP)\NP</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]\NP</div>
<div class="rule" title="Forward Application">&gt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]</div>
<div class="rule" title="Backward Application">&lt; <sup>0</sup>
</div>
</div></td></tr>
</table></td>
<td class="daughter daughter-right"><table class="constituent lex" data-token="." data-from="22" data-to="23" data-cat="S[dcl]\S[dcl]">
<tr><td class="token">.</td></tr>
<tr><td class="cat" tabindex="0">S[dcl]\S[dcl]</td></tr>
<tr><td class="span-swiper"> </td></tr>
</table></td>
</tr>
<tr><td colspan="2" class="rulecat"><div class="rulecat">
<div class="cat">S[dcl]</div>
<div class="rule" title="Backward Application">&lt; <sup>0</sup>
</div>
</div></td></tr>
</table> </div>

Use with der.css.

\begin{tikzpicture}[ampersand replacement=\&]
	\matrix [column sep=9pt] at (0, 0) {
		\lexnode*{idm13}{Mij}{\catNP}{} \&
		\lexnode*{idm54}{maakt}{(\catS[dcl]\?\catNP)/(\catS[b]\?\catNP)}{} \&
		\lexnode*{idm79}{het}{\catNP}{} \&
		\lexnode*{idm87}{niet}{(\catS[dcl]\?\catNP)\?(\catS[dcl]\?\catNP)}{} \&
		\lexnode*{idm101}{uit}{(\catS[b]\?\catNP)\?\catNP}{} \&
		\lexnode*{idm113}{.}{\catS[dcl]\?\catS[dcl]}{} \\
	};
	\unnode*{idm68}{idm79-cat}{\FTR}{(\catS[b]\?\catNP)/((\catS[b]\?\catNP)\?\catNP)}{}
	\binnode*{idm41}{idm54-cat}{idm68}{\FC{1}}{(\catS[dcl]\?\catNP)/((\catS[b]\?\catNP)\?\catNP)}{}
	\binnode*{idm28}{idm41}{idm87-cat}{\BXC{1}}{(\catS[dcl]\?\catNP)/((\catS[b]\?\catNP)\?\catNP)}{}
	\binnode*{idm21}{idm28}{idm101-cat}{\FC{0}}{\catS[dcl]\?\catNP}{}
	\binnode*{idm8}{idm13-cat}{idm21}{\BC{0}}{\catS[dcl]}{}
	\binnode*{idm3}{idm8}{idm113-cat}{\BC{0}}{\catS[dcl]}{}
\end{tikzpicture}

Use with ccgsym.sty and tikzlibraryccgder.code.tex.

Sentence

Parse

Translations